(2x+5)(4x^2-9)=0

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Solution for (2x+5)(4x^2-9)=0 equation:


Simplifying
(2x + 5)(4x2 + -9) = 0

Reorder the terms:
(5 + 2x)(4x2 + -9) = 0

Reorder the terms:
(5 + 2x)(-9 + 4x2) = 0

Multiply (5 + 2x) * (-9 + 4x2)
(5(-9 + 4x2) + 2x * (-9 + 4x2)) = 0
((-9 * 5 + 4x2 * 5) + 2x * (-9 + 4x2)) = 0
((-45 + 20x2) + 2x * (-9 + 4x2)) = 0
(-45 + 20x2 + (-9 * 2x + 4x2 * 2x)) = 0
(-45 + 20x2 + (-18x + 8x3)) = 0

Reorder the terms:
(-45 + -18x + 20x2 + 8x3) = 0
(-45 + -18x + 20x2 + 8x3) = 0

Solving
-45 + -18x + 20x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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